Heating and heat pump tools
Heat pump vs electric heater
Is a heat pump cheaper to run than an electric heater?
For the same delivered heat, yes — by a factor set by the heat pump’s seasonal performance. A 1,500 W resistance heater running 8 hours a day uses 12.0 kWh per day and 365 kWh over an average month, all of which becomes heat, costing $65.74. A heat pump with a seasonal performance factor of 3.0 delivers that identical 365 kWh of heat from 122 kWh of electricity, costing $21.91 — $43.83 less per month at $0.180/kWh. Equipment and installation costs are excluded.
Same heat, different electricity
| System | Electricity used | Running cost | Difference vs resistance |
|---|---|---|---|
| Electric resistance heater | 365 kWh | $65.74 | — |
| Heat pump, SCOP 2.0 | 183 kWh | $32.87 | $32.87 |
| Heat pump, SCOP 2.5 | 146 kWh | $26.30 | $39.45 |
| Heat pump, SCOP 3.0 | 122 kWh | $21.91 | $43.83 |
| Heat pump, SCOP 3.5 | 104 kWh | $18.78 | $46.96 |
Why the physics allows this
At the point of use, electric resistance heaters convert essentially all of the electricity they consume into heat, and they cannot exceed one-for-one: every joule in becomes a joule of heat. Two heaters drawing the same 1,500 W therefore deliver approximately the same total heat while they are drawing that power, although controls, cycling and heat distribution can change comfort and total energy use over time.
A heat pump does something different. It uses electricity to run a compressor that moves heat from outdoor air into the house. Because most of the delivered heat is collected rather than generated, a unit of electricity can deliver two, three or four units of heat. That ratio is the coefficient of performance, and it falls as the outdoor temperature drops, because there is less ambient heat to collect and a bigger temperature lift to achieve.
Use a seasonal figure, not a rated peak
Run the comparison on your own numbers
Your inputs
Annual electricity attributable to heating. If your bill does not separate heating from other loads, this will need to be estimated.
1.0 for electric resistance heating — baseboards, panel heaters, electric furnaces.
A season average, not a rated peak COP. Actual seasonal performance depends on climate, flow temperature, system design and controls.
$720.00
lower running cost per year
Same 6,000 kWh of heat delivered, 67% less electricity cost
- Heat delivered
- 6,000 kWh
- Electricity now
- 6,000 kWh
- Electricity with heat pump
- 2,000 kWh
- Running cost change
- −$720.00
| System | Performance factor | Electricity used | Running cost |
|---|---|---|---|
| Current system | 1.0 | 6,000 kWh | $1,080 |
| Heat pump | 3.0 | 2,000 kWh | $360.00 |
Lower running cost under these assumptions
Method
- Heat delivered: 6000 kWh of heat
- Current: 6000 ÷ 1 = 6000 kWh electricity → 1080 USD
- Heat pump: 6000 ÷ 3 = 2000 kWh electricity → 360 USD
- Difference: 720 USD
Assumptions
- Seasonal performance factor of 3 for the heat pump — a season average, not a rated peak COP.
- Current system performance factor of 1.
- Both systems are assumed to deliver the same amount of heat into the home.
- Electricity rate of 0.18 USD/kWh for both systems, with no standing-charge or tariff difference.
- Installation cost, maintenance, distribution losses and comfort differences are not included.
What can change the result?
- Seasonal performance factor, which varies with climate and system design
- Flow temperature — high-temperature radiators reduce performance significantly
- Your electricity tariff and whether heating has a separate rate
- Backup resistance heat used during the coldest hours
- Building insulation, which determines the heat demand both systems must meet
Your next decision
- See what a plug-in space heater actually adds to a billThe resistance side of this comparison, priced across a full rate range and thermostat duty cycle.
- Estimate annual savings from your heating consumptionWhole-year comparison with SCOP sensitivity.
- Cost your existing resistance heatingThe baseline this comparison depends on.
- Read why COP and SCOP are not interchangeableThe assumption that most distorts results.
- Understand how output and efficiency change in cold weatherWhy a single COP cannot describe a heating season.