Electrical units and conversion

How many amps does a refrigerator use?

A running answer, a start-surge answer and an average answer — because a fridge spends most of its life drawing none of the three.

How many amps does a refrigerator use?

A typical full-size household refrigerator draws about 1.6 A at 120 V or 0.8 A at 230 V while its compressor is actually running, based on 150 W of compressor input power at a motor power factor of 0.80. Across the normal range of 80 W to 250 W that is 0.8–2.6 A at 120 V. But the compressor only runs about 35% of the time, so the average current over a day is nearer 0.5 A — and for a fraction of a second at each start it spikes to roughly 8 A. Those are three different correct answers to the same question, and which one you need depends on what you are sizing.

The three numbers, side by side

Amps = watts ÷ (volts × 0.80). Wattages from appliances-1.0.0; currents computed by currentEngine-1.0.0.
State	Input power	Amps at 120 V	Amps at 230 V
Running, low end of the range	80 W	0.83 A	0.43 A
Running, typical	150 W	1.56 A	0.82 A
Running, high end of the range	250 W	2.60 A	1.36 A
Compressor start surge	800 W	8.3 A	4.3 A

Which number do you actually need?

Sizing a circuit or breaker: the nameplate current and your local electrical code govern actual breaker and wire sizing; running current only helps explain normal load. Sizing an inverter, battery or generator: the start surge matters for source capability, not the running figure. Estimating a bill: none of them — use the average, or better, use kWh directly.

Why the nameplate reads higher than this

The label on the back states a maximum rated current, which includes defrost heaters and worst-case conditions. It is a rating for the appliance's protection, not a measurement of what it draws on a normal day. A nameplate reading 6 A on a fridge that actually runs at 1.6 A is not a contradiction.

Duty cycle is the part the other answers leave out

A refrigerator is plugged in for all 24 hours but its compressor is not. It cycles: it pulls the cabinet down to temperature, shuts off, and restarts when the cabinet warms. A typical unit runs somewhere between 25% and 45% of the time. That is why the current is genuinely 1.6 A when you measure it with a clamp meter during a compressor run, and genuinely 0.5 A when you average it over a day. Neither reading is wrong; they are answers to different questions.

The power factor matters here for the same reason. A compressor is an induction motor, so part of the current it draws magnetises the motor and does no work. At a power factor of 0.80, 150 W of real work needs 1.56 A rather than the 1.25 A that a plain watts ÷ volts division would give — about 25% more current for the same cooling. Converters that omit the power factor understate a fridge by roughly that margin.

Run the numbers for your own unit

Enter the wattage from your own appliance, or its nameplate current to work backwards to watts. Keep the load type set to motor-driven for anything with a compressor in it.

Your inputs

Direction

Power

Supply voltage

Nominal supply voltage. 120 V and 240 V are the North American single-phase values; most of Europe, the UK and Australia use 230 V.

Common supply voltages

Type of load

Sets the power factor used below: 1.00.

12.50

amps at 120 V

1.5 kW drawn at a power factor of 1.00

Exact given your inputs

Current: 12.50 A
Real power: 1.5 kW
Apparent power: 1,500 VA
Fits a breaker of: 20 A

Why the power factor is on this page at all

A purely resistive load draws current in phase with the voltage, so the power factor is 1 and watts ÷ volts is exact. At a power factor of 1 the volt-amps and the watts are the same number, so watts ÷ volts is the complete answer. Switch the load type above to see how far apart they move for a motor.

What the breaker column means, and what it does not

A circuit serving a continuous load may be loaded to 80% of its breaker rating, so 12.50 A needs at least a 20 A circuit on that basis alone. This is arithmetic, not a wiring design: conductor size, ambient temperature, derating, other loads on the same circuit and local code all change the answer. Do not size a circuit from this page.

Method

1500 W ÷ (120 V × 1) = 12.5 A
120 V × 12.5 A = 1500 VA apparent power

Engine currentEngine-1.0.0. Values are computed at full precision and rounded only for display.

Assumptions

Single-phase AC (or DC) at 120 V nominal. Real supply voltage varies, and current moves inversely with it: the same load draws more amps on a sagging supply.
Power factor of 1, so watts and volt-amps are the same number. This holds for resistive loads only.
Steady running current. Motor starting current is several times this figure for a fraction of a second and is not included here.

What can change the result?

Actual supply voltage, which sags under load and varies by region and time of day
Real power factor of your specific unit, which changes with how heavily it is loaded
Motor starting current, which is several times the running figure for a fraction of a second
Whether the nameplate lists maximum draw or typical draw — most list the maximum